MIRROR: Download from MEGA
I think I know how but tell me if this is right.
There is an equation, I have found the energy absorbed released by using Q=mc delta t in a coffee cup calorimeter.
I have also found the moles of my reactant ( I reacted Hcl with MgO) using
mass molar mass = moles. so I have found the moles of MgO.
To find the Delta Hr (heat of reaction) since it is in kJ mol
do I just convert my J (from my energy) to kJ then divide it by the moles of the MgO
another view on heaven and hell
3dflash.co.uk
www.shelterforum.or.ke
www.babeposting.com
www.austprostassc.com.au
rajcoffee.com
roxorx.co.uk
www.freeclassifiedadsforum.com
www.conceptcoop.com
oubraim.free.fr
abipunktur2005.de
Keep2share Premium PRO Account